Adding easy puzzles

puzzles/easy/mars-lander-episode-1.cpp

@@ -0,0 +1,58 @@
+// https://www.codingame.com/ide/puzzle/mars-lander-episode-1
+// Xavier Morel - 2016-03-12
+
+#include <iostream>
+#include <string>
+#include <vector>
+#include <algorithm>
+
+using namespace std;
+
+typedef struct {
+    int x;
+    int y;
+} Coords;
+
+/**
+ * Auto-generated code below aims at helping you parse
+ * the standard input according to the problem statement.
+ **/
+int main()
+{
+    int N; // the number of points used to draw the surface of Mars.
+    cin >> N; cin.ignore();
+    int landing_start = 0;
+    int landing_end = 0;
+    int landing_y;
+
+    for (int i = 0; i < N; i++) {
+        int LAND_X; // X coordinate of a surface point. (0 to 6999)
+        int LAND_Y; // Y coordinate of a surface point. By linking all the points together in a sequential fashion, you form the surface of Mars.
+
+        cin >> LAND_X >> LAND_Y; cin.ignore();
+        if ((i == 0 || landing_y != LAND_Y) && (landing_end - landing_start < 1000)) {
+            landing_start = LAND_X;
+            landing_y     = LAND_Y;
+        } else if (landing_y == LAND_Y) {
+            landing_end = LAND_X;
+        }
+    }
+
+    // game loop
+    while (1) {
+        Coords pos;
+        int HS; // the horizontal speed (in m/s), can be negative.
+        int VS; // the vertical speed (in m/s), can be negative.
+        int F; // the quantity of remaining fuel in liters.
+        int R; // the rotation angle in degrees (-90 to 90).
+        int P; // the thrust power (0 to 4).
+        cin >> pos.x >> pos.y >> HS >> VS >> F >> R >> P; cin.ignore();
+
+        int power = 0;
+        if (VS < -39) {
+            power = 4;
+        }
+
+        cout << "0 " << power << endl; // R P. R is the desired rotation angle. P is the desired thrust power.
+    }
+}